What is the directrix of the parabola given by the equation y = –5x2 + 60x – 176?
answer choices: x= 3 19/20 y= 4 1/20 x=4 1/20 y= 2 19/20 Im completely lost on finding the directrix
the last one is 3 19/20 (not 2 19/20)
Find the vertex, then find the focus. Finally directix.
http://www.sciencebuddies.org/science-fair-projects/project_ideas/CompSci_img011.gif
here we go again lets go slow
please. I understand the focus more. But this confused me.
\[y = -5x^2 + 60x -176\] what is your job? to make it look like \[4p(y-k)=(x-h)^2\] this is going to take some algebra
first add \(176\) to both sides
I just get confused with all the variables. I know how to solve equations and stuff but the formual confuses me
actually i have a better idea to make it somewhat easier but you are going to have to complete the square no matter what
okay thankyou!
ok now i see i made a bush league mistake. lets start again
okay
\[y = -5x^2 + 60x -176\] \[y=-5(x^2-12x)-176\] \[y=-5(x-6)^2+180-176\] \[y=-5(x-6)^2+4\] \[y-4=-5(x-6)^2\] \[-\frac{1}{5}(y-4)=(x-6)^2\]
now it is in the form you want
we see from our eyeballs that the vertex is \((6,4)\) and we compute \(p\) as before by solving \(4p=-\frac{1}{5}\) so \(p=-\frac{1}{20}\)
okay I understand that. now how do you find the directrix though? Im not lost yet
parabola opens down, so the focus is \(\frac{1}{20}\) units below the vertex and directrix is \(\frac{1}{20}\) units above
focus is therefore \((6,4-\frac{1}{20})\) or \((6,3\tfrac{19}{20})\)
and directrix is \(y=4+\frac{1}{20}\) or \(y=4\tfrac{1}{20}\)
ohh okay! its starting to make more sense nnow! thankyou again for all your help!
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you really need a picture to see what is going that is a crappy one here is a better one http://www.wolframalpha.com/input/?i=+y+%3D+%E2%80%935x2+%2B+60x+%E2%80%93+176
if you take the link i sent, type "parabola" before the equation, you will get everything you want wont help on a test or quiz though
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