Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

PLEASE help. state the value of the discriminant and then describe the nature of the solutions to -16x^2-7x+11=0

OpenStudy (anonymous):

discriminant =b^2-4ac

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

@tholland

OpenStudy (anonymous):

if b^2-4ac>0 then two real solutions if b^2-4ac=0 then one real solution if b^2-4ac<0 then no real solution

OpenStudy (anonymous):

so it has two real solutions? two imaginary solutions, or one real solution? the question is confusing to me

OpenStudy (amistre64):

what value do you get for the discriminant?

OpenStudy (anonymous):

b^2-4ac

OpenStudy (amistre64):

thats not the value, that is a general formula; fill in the specific from the equation given to find the value

OpenStudy (anonymous):

then i am not sure how to get the value

OpenStudy (amistre64):

have you studied the material that this quiz is about?

OpenStudy (amistre64):

the general setup of the quadratic equation is of the form ax^2 +bx + c; use the equation given to determine that specific values for a b and c

OpenStudy (amistre64):

-16 x^2 -7 x + 11 a x^2 +b x + c use the equation given to define the values of a b and c ...

OpenStudy (precal):

another way to learn about the discriminant and the roots (aka solutions) is to look at the graph of your equation |dw:1344699457609:dw| if the graph of the equation crosses in 2 places on the x axis it has 2 solutions |dw:1344699511582:dw| if the graph of the equation crosses in 1 place on the x axis it has 1 solution |dw:1344699556457:dw| if the graph of the equation does not cross the x axis then it has no solution or aka complex solution before graphing calculators were invented, mathematicians used the discriminant to figure out how many solutions a quadratic has without graphing it or solving for the roots

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!