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Quick question on the multiplication of trig functions.
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I was getting the determinant of a matrix.This left me with \[((\cos(3t).3\cos(3t))-((\sin(3t).-3\sin(3t))\]
Just wondering how do I multiply this out
Wolfram doesn't break it down for me. Just gives me the result.
3cc--3ss = 3(c^2+s^2)
using the trig id that s^2+c^2 = 1 .... id say that leaves 3
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@amistre64 Are you saying 1sin^2+1cos^2=1???
i hope so .... :)
Well the answer is 3 but the calculator says otherwise
I'm getting 0.98...........
Which I guess is close to 1, I guess.
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its prolly due to input errors
the (3t) part is useless jargon in this case
sin.sin=sin^2 cos.cos=cos^2 sin^2+cos^2=1
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