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Which of the following is not a way to represent the solution of the inequality 3(2x - 1) greater than or equal to 4(2x - 3) - 3?
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x 6 6 x A number line with a closed circle on 6 and shading to the left. A number line with a closed circle on 6 and shading to the right.
\[\Huge{3(2x-1)\ge 4(2x-3)-3}\]
\[\Huge{6x-3 \ge 8x-15}\]
\[\Huge{6x-8x \ge -15+3}\]
\[\Huge{-2x \ge -12}\]
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\[\Huge{x \ge 6}\]
hence , D is the answer :D
gt it @cedric ?
ok
wait lemme see
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k!
so is it because the 6 times 2 makes the 12?
yeah!
haha Nice! thanaks man, im giving you a medal
LOL ! nice to hear :)
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