Question

HELP ME OMG
a particle travels along a straight line with its acceleration at time t seconds equal to (3t+2) m/s2. the particle has an initial positive velocity and travels 30m in the fourth second. Find the velocity of the object when t=5

Answer 1

anyone?

Answer 2

insufficient data

Answer 3

integrate that function you'll get velocity at t=5...since velocity \[v=\int\limits_{0}^{t} adt\]

Answer 4

insufficient data? whaaat. you're just giving up

Answer 5

@ghazi i cant just integrate blindly, it will give me an unknown constant.

Answer 6

@ghazi, doesnt that give you velocity = 85 m/s?

Answer 7

@ mathsloser56, nah it wont, its a definite integral

Answer 8

see limit of integration will be 0 to 5 and you'll get v= 47.5m/s at t=5

Answer 9

after integrating, you'll get (3t^2/2)+2t....now put t=5

Answer 10

ok....velocity=integral of acceleration....which gives,v=3t*t/2+2t+c...where c is constant...so they should have given conditions to find initial vel=c....but they gave values of displacement,for which we need to integrate once more and now there will be two unknowns...so two conditions required...r u following??

Answer 11

@ghazi but thats assuming you start with 0 velocity. the question says it has positive velocity

Answer 12

@hartnn yes. i guess so

Answer 13

this is not yet solved.

Answer 14

im tempted to spam this box to get the attention

Answer 15

ok got the answer 52. turns out im the best around here after all ;p

Answer 16

wouldnt you agree?

Answer 17

\[\sqrt{-1} + 2^{3} + \sum_{}^{} + \pi \] and it was delicious

Answer 18

i ate some pie :)