find the first 4 terms
$$a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}$$

Question

find the first 4 terms 
$$a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n(a_n)}$$

anonymous · Answer

i got my answer but apparently i was wrong
this from @lopez_hatesmath

anonymous · Answer

maybe some fresh eyes would help

anonymous · Answer

nvm sorry to bother you

anonymous · Answer

:(

anonymous · Answer

i got it

anonymous · Answer

swagg

anonymous · Answer

it was this 
$$a_1=\frac{3}{2}; a_{n+1}=\frac{n^2+1}{n}\times a_n$$

anonymous · Answer

that is, the $a_n$ was in the NUMERATOR

anonymous · Answer

so now it is not so bad
replace $n=1$ on the right hand side to get $a_2$

anonymous · Answer

you get 
$$a_2=\frac{1^2+1}{1}\times \frac{3}{2}$$
$$a_2=2\times\frac{3}{2}$$
$$a_2=3$$

anonymous · Answer

now replace $n$ by 2 on the right hand side to get 
$$a_3=\frac{2^2+1}{2}\times 3$$
$$a_3=\frac{5}{2}\times 3$$
$$a_3=\frac{15}{2}$$

anonymous · Answer

how are we doing so far?

anonymous · Answer

good :)

anonymous · Answer

one more? 
$$a_4=\frac{3^2+1}{3}\times \frac{15}{2}$$
$$a_4=\frac{10}{3}\times \frac{15}{2}$$
$$a_4=25$$

anonymous · Answer

okayy i got it!

anonymous · Answer

not so bad 
that is the idea, i thought the term was in the denominator which is why i was screwing it up

anonymous · Answer

gotcha thanks for the help man.

anonymous · Answer

yw 
good luck with the next one, but it works the same so you should be good to go