Question

f(x) = (x - 2)2 + 2

All real numbers

y ≥ 0

y < 2

y ≥ 2

Answer 1

What exactly is it that you don't understand

Answer 2

i think it is y ≥ 2 but my question is if i did it right

Answer 3

looking at [ (x - 2)^2 ], what type of numbers are we going to get for every value "x"

Answer 4

since i am squaring, i will always get a number bigger or equal to 0.

Answer 5

the (y - 2)^2 cannot be negative for real y
so its minimum values is 0

Answer 6

y ≥ 0

Answer 7

thanks guys

Answer 8

so y >= 2 for real f(y)

Answer 9

adding a 2 to the number will make it bigger oy equal to 2.


so y [greater than OR equal to] 2

Answer 10

thanksssss :)

Answer 11

yes