please see attached..

the answer to this question is 6.8A from b to a. could you guys show me how it came up with 6.8A from b to a?

Question

please see attached..

the answer to this question is 6.8A from b to a. could you guys show me how it came up with 6.8A from b to a?

anonymous · Answer

http://i46.tinypic.com/9r21c6.jpg

anonymous · Answer

ok $$V_{ab}=17.4$$
this means $$emf-V_r=V_{ab}$$
so we need to find V_r

V=IR
and solve for I
because the current running through the resisitance is the same as the current running through the battery

anonymous · Answer

Yep! I just figured it out. *notes really helps! XD* for the direction of the current, is it always from negative to positive?

anonymous · Answer

do you mean in general or across the battery?

anonymous · Answer

both. I just don't get it why the direction is from b to a.

anonymous · Answer

|dw:1344750402828:dw|
it will always be in that direction, unless Vab was a negative voltage,
its kinda something you have to memorize