Solve the differential equation:
(y+siny) y' = x + x^3

I got to:
(1/2) y^2 - cosy = (1/2) x^2 + (1/4) x^4 + C

I'm new to this differential equation stuff :P

Question

Solve the differential equation:
(y+siny) y' = x + x^3

I got to:
(1/2) y^2 - cosy = (1/2) x^2 + (1/4) x^4 + C

I'm new to this differential equation stuff :P

anonymous · Answer

you got it correct.

alexwee123 · Answer

yup you got it ^.^

anonymous · Answer

Can I take that any further down to just get an equation in y = form?

alexwee123 · Answer

depends on your book :/.... do you have the answer for this problem?

anonymous · Answer

They wanted to charge me another $70 -.-

alexwee123 · Answer

lol that sucks :o

anonymous · Answer

I'll just leave it as y^2 - 2cosy = x^2 + (1/2)x^4 + 2C
Haha :)

alexwee123 · Answer

well there's always this site http://www.wolframalpha.com/ for reference if you need it :)

anonymous · Answer

dont give in to the greediness stay strong lol

anonymous · Answer

Wolfram likes to interpret y as a constant and not a variable, in my experience haha.