Limit test for series?
On this question I have \[\sum_{n=1}^{\infty} \frac{6n}{n+9}\]
no chance
when I look at what I did before I see that I just did like what we would do before doing L'Hospitals rule and divide out by the highest "n" so (6/n)/((n/n) + (9/n))?
no chance wut? :p
the degree of the denominator must be greater than the degree of the numerator by more than one
okay I see I got this q wrong, good because I was konfused hahaha.
to do what sir?
in this case the degrees are the same. in fact the limit as \(n\to \infty=6\) not 0 which is necessary (but not sufficient) for convergence
okay I see.. So there is a limit test then?
if in the limit the individual terms do not go to zero, then there is no way for the infinite sum to converge
mhm
you are trying to add an infinite number of numbers , each of which gets closer and closer to 6, there is no way for this to be finite
nth term test?
i have never heard of such a thing, but at the very least if you want any hope of convergence for an infinite sum, the terms must go to zero
set n = infinity and see where it goes? if it's 0 it converges, if it's anything else it diverges?
oh no!
Thyat's what my book calls it :p.
if the terms do not go to zero, then it does not converge the converse is false famous example \[\sum\frac{1}{n}\] the harmonic series diverges, even though the terms go to 0 in the limit
mhm
I understand.
I'm still confused about this limit test business... does it exist?
so the terms must go to zero, but also they must go to zero fast enough however in your example \(\lim_{n\to\infty}\frac{6n}{n+p}=6\) so the sum does not converge
yeah that' sthe nth term test :p.
as my book calls it..
there are many tests for convergence comparison test ratio test root test integral test cauchy "condensation" test etc
The ones I've learned are nth term test, geo series test, ratio, integral, power, and then the taylor/maclauren.
it is a rather large topic
alternating
yeah that too
I'm trying to bone up on the rest of it for myfinal tomorrow.... That's why I was soo konfused about this limit series... but it doesn't exist LOL.
Weird thing is I got the same answer when I did it the other way.... (6n/n)/((n/n) + (9/n))? = 6/(1+(9/n(infinity))) ===== 6/(1+ 0) = 6?.... @satellite73
Join our real-time social learning platform and learn together with your friends!