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Mathematics 16 Online
OpenStudy (konradzuse):

Limit test for series?

OpenStudy (konradzuse):

On this question I have \[\sum_{n=1}^{\infty} \frac{6n}{n+9}\]

OpenStudy (anonymous):

no chance

OpenStudy (konradzuse):

when I look at what I did before I see that I just did like what we would do before doing L'Hospitals rule and divide out by the highest "n" so (6/n)/((n/n) + (9/n))?

OpenStudy (konradzuse):

no chance wut? :p

OpenStudy (anonymous):

the degree of the denominator must be greater than the degree of the numerator by more than one

OpenStudy (konradzuse):

okay I see I got this q wrong, good because I was konfused hahaha.

OpenStudy (konradzuse):

to do what sir?

OpenStudy (anonymous):

in this case the degrees are the same. in fact the limit as \(n\to \infty=6\) not 0 which is necessary (but not sufficient) for convergence

OpenStudy (konradzuse):

okay I see.. So there is a limit test then?

OpenStudy (anonymous):

if in the limit the individual terms do not go to zero, then there is no way for the infinite sum to converge

OpenStudy (konradzuse):

mhm

OpenStudy (anonymous):

you are trying to add an infinite number of numbers , each of which gets closer and closer to 6, there is no way for this to be finite

OpenStudy (konradzuse):

nth term test?

OpenStudy (anonymous):

i have never heard of such a thing, but at the very least if you want any hope of convergence for an infinite sum, the terms must go to zero

OpenStudy (konradzuse):

set n = infinity and see where it goes? if it's 0 it converges, if it's anything else it diverges?

OpenStudy (anonymous):

oh no!

OpenStudy (konradzuse):

Thyat's what my book calls it :p.

OpenStudy (anonymous):

if the terms do not go to zero, then it does not converge the converse is false famous example \[\sum\frac{1}{n}\] the harmonic series diverges, even though the terms go to 0 in the limit

OpenStudy (konradzuse):

mhm

OpenStudy (konradzuse):

I understand.

OpenStudy (konradzuse):

I'm still confused about this limit test business... does it exist?

OpenStudy (anonymous):

so the terms must go to zero, but also they must go to zero fast enough however in your example \(\lim_{n\to\infty}\frac{6n}{n+p}=6\) so the sum does not converge

OpenStudy (konradzuse):

yeah that' sthe nth term test :p.

OpenStudy (konradzuse):

as my book calls it..

OpenStudy (anonymous):

there are many tests for convergence comparison test ratio test root test integral test cauchy "condensation" test etc

OpenStudy (konradzuse):

The ones I've learned are nth term test, geo series test, ratio, integral, power, and then the taylor/maclauren.

OpenStudy (anonymous):

it is a rather large topic

OpenStudy (konradzuse):

alternating

OpenStudy (anonymous):

yeah that too

OpenStudy (konradzuse):

I'm trying to bone up on the rest of it for myfinal tomorrow.... That's why I was soo konfused about this limit series... but it doesn't exist LOL.

OpenStudy (konradzuse):

Weird thing is I got the same answer when I did it the other way.... (6n/n)/((n/n) + (9/n))? = 6/(1+(9/n(infinity))) ===== 6/(1+ 0) = 6?.... @satellite73

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