Question

showing how to work it

Answer 1

so we can do everything one step at a time

Answer 2

the numbers and then the x's and then the y's

Answer 3

so \(\huge {3 \over 9} \) can be reduced to?

Answer 4

yes 1/2

Answer 5

\( \huge { 1 \over 3}\)

Answer 6

or that

Answer 7

now we know that when dividing exponents if they have the same base you keep the base and subtract the exponents
So \( \huge { x^2 \over x} \) =?

Answer 8

x

Answer 9

yes and \( \huge {y\over y^2} \) =?

Answer 10

y

Answer 11

\( \huge {y^1 \over y^2} \)
so that wld be 1-2=-1
so our answer wld be \(y^{-1}\)

Answer 12

\( \large y^{-1}={1 \over y} \)

Answer 13

soooo all in allll our solution shld look as follows:
\( \large {1\over 3} *{1 \over y}*x = \huge {x \over 3y} \)

Answer 14

hahaha like once you get it u dont have to do all these steps. Liek you just do it in ur brain

Answer 15

hahah yea just summer and a year of non algebra just makes you forget everything