What is the value of x in the solution to the following system of equations? x − 2y = 2 3x + y = 6
The first equation can be turned into x=2+2y so then substitute 2+2y into the second equation and solve.
so 3(2+2y)=6-y?
An easy way to find x is to completely eliminate y using systems of equations. Is there any way to manipulate the equations so that when added, y is eliminated?
flow, your substitution is fine
to eliminate y double the 2nd equation and add to the 1st eauation x - 2y = 2 6x + 2y = 12 ---------------------- 7x = 14 solve for x then substitute to find y
but to find "x", you want to define y(x) for a sunstitution
x − 2y = 2 3x + y = 6 <-- simpler to use y(x) = 6-3x x − 2y(x) = 2 x − 2(6-3x) = 2
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