Write the equation of the line that is parallel to the line 3x − y = −3 and passes through the point (4, −2). y = −1/3x − 6 y = −1/3x − 14 y = 3x − 6 y = 3x − 14
okay so you got y by itself, thats a good start, now to have two parallel lines, the slopes of the lines must be the same.
then you use the point slope form of the equation of a line
can you work it out for me dont get it at all
@ghazi
3x-y=d now just substitute (4,-2) at x any y to get d ...see what you get?
ohh!
the answer is d right
correct
i have more is that coool
Write the equation of the line that is parallel to the line y = −3x + 12 and passes through the point (−1, 6). y =1/3 x + 7 y = −3x + 3 y =1/3 x + 3 y = −3x + 7
@ghazi
b
Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2). y = x2/3 − 10 y = x2/3 + 10 y = −3/2x − 10 y = −3/2x + 10
@ghazi
d
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3). y = 2x + 6 y = −1/2x + 3 y = −1/2x + 6 y = 2x + 3 @ghazi
c
Select the inequality that corresponds to the given graph. 5x + 7 2 and 10x 30 6x + 7 25 or 2x - 8 < -4 4x + 10 6 or 5x - 6 14 37 8x - 3 61
nvm forget tha one
-7y - 17 > 11 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution. @ghazi
y>4
would you graph to the right with and open circle ?
|dw:1344894037758:dw| but dude i am not damn sure about this one :)
Join our real-time social learning platform and learn together with your friends!