Question

Pre-Calculus HELP!!

Answer 1

^^^^

Answer 2

https://media.glynlyon.com/g_prc_2012/1/u17.gif
this also goes with the problem

Answer 3

\(a\) does not have to be negative
it just cannot be zero

Answer 4

what are you talking about? Im really confused.

Answer 5

i read \(\{(a,b):ab=12\}\)

Answer 6

means the set of all ordered pairs \((a,b)\)whose product is 12

Answer 7

so for example \((2,6),(3,4),(5,\frac{12}{5}), (12,1), (-4,-3)\) all belong there

Answer 8

you are asked for the "domain" meaning the possible values for \(a\) the first coordinate

Answer 9

okay I think im getting it a little

Answer 10

you can make \(a\) any number that you like, because whatever you choose for \(a\) you can put \(b=\frac{12}{a}\) it will work
HOWEVER you cannot let \(a=0\) because if \(a=0\) you cannot solve \(0\times b=12\)

Answer 11

in other words, \(a\) can be any number you choose, except for \(0\) because there is no way \(0\times b=12\)

Answer 12

btw this also explains why you cannot divide by 0
if \(ab=12\) then \(b=\frac{12}{a}\) but \(\frac{12}{0}\) in not defined because there is no way that \(0\times b=12\)

Answer 13

ok they arent allowing me to change the 0, so it would be \[\neq 0\]

Answer 14

yes

Answer 15

Thank you I think I have it now!!!