D= vit +1/2at^2 Solve for vi the solve for a
\[D=v_it+\frac{1}{2}at^2\] solving for vi start by subtracting 1/2at^2 from both sides \[D-\frac{1}{2}at^2=v_\it+\frac{1}{2}at^2-\frac{1}{2}at^2\] \[D-\frac{1}{2}at^2=v_it\] then divide t from both sides
Ok then what
then you've solved for v_i do the same kind of process for solving for a when being asked to solve for any variables, it means you need to isolate that variable so its by itself on one side. just remember if you ever do something to one side, you always have to do it to the other
Do I divide t on both sides
for which problem? v_i?
Yes
yes you need to divide by t to both sides, that way v_i will be by itself
So will it be d-.5at2/t=vi
@Com
@completeidiot
Is my Nswer above sorrect
Correct And answer
it will look like \[\frac{D-\frac{1}{2} at^2}{t}=v_i\] t is divided over the whole thing
What about the second one could you guide me through that 2
ok, we need to solve for a so that means you should subtract v_it from both sides
do you understand why we're subtracting v_i*t ?
Yes to get a alone
ok then what will you do to "a"?
Nothing yet , I'm not sure
ok you have 1/2* a* t^2 we need to get "a" alone what could you multiply by or divide by to get a alone
What. Does the asters mean
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