if a^2 is even....prove that a is even...
it's known to everyone that the square of a even number is even
if a = 2k =>a^2 = 4k^2 = 2*something =>even hence proved..
u r showin proof to..if a is even...show that a^2 is even........:D
o.O ??
It's the same. lol
\(\LARGE{a^2=even \space number}\) then the number whose square is \(a^2\) is also even
If \(a\) is even, then \(a\) is in the form \(2k\). \[2k \times 2k = 4k^2 = 2(2k^2)\]
maybe your next ques will be: if a is even prove that a+1 is odd!! or even if a is even prove that 2a is even!! ;)
Haha, those are axioms! ^
in "or even" i didnt mean the mathematical meaning of "even" !! :P
p->q is not the same as q->p.... i.e.,if A=40degrees,..then A is acute..... where as if A is acute then S is 60 degrees.........????:DDDD
sorry 40 degrees..
i thing B is 66.75 radians here ??
nevermind,,am outa here!! :D
Didn't I tell the proof?
haha ! some problem is with this site
well now look @ this site @anusha.p u will gt ur answer :)
Oh yes! I have this proof posted too as a tutorial!
@jiteshmeghwal9 i want it by direct proof....
yeah ! these site is providing diffrent types of answers
Wait, no. Direct proofing is not possible in this case!
Okay, I lied. It actually is... but it's a long one. "To prove: For all whole numbers x, if x2 is even then x is even. A direct proof is difficult, so a proof by contrapositive is preferable." http://en.wikipedia.org/wiki/Proof_by_contrapositive
& u have gave u the proof using a axiom that the square of a even number is even
If you are talking about the \(a = 2k\) proof, then see above.
Given : \(a^2\) is even then from above axiom the number whose square is \(a^2\) is also even number
And then we continue with \(a = 2k\).
too small proof @anusha.p :D
well i m also nt sure. am i right @ParthKohli ???
Yes.
k!
so..wat do u say finally???
In this case, if we are given a hypothesis that looks like "If \(a^2\) is even, then \(a\) is even", we may rearrange(only in this case) to make it look like "If \(a\) is even, then \(a^2\) s even too." Presume that \(a = 2k\) where \(k\) is an integer.\[a^2 \implies (2k)^2 \implies 4k^2 = 2(2k^2) \]We know that this is an even number since 2 is a factor.
can we rearrange......? i mean is it allowed....if so..how??
It's just mind-work and logic. Think about it, and don't think about \(p\Rightarrow q\) thing.
but the actual thing here is the implication only....na
"If \(a^2\) is even, then \(a\) is even" is just a fancy way to say "If a is even, then \(a^2\) is even too."
Think about it for a while.
\[\Large{a^2=a \times a}\]Since \(a^2\)is even number therefore a is also even because when we multiply anything with an even no. we get an even number ;)
???
@TheViper That's a nice way, but you gotta use these statements as less as possible. "we multiply anything with an even no. we get an even number" is a theorem, and not an axiom. Rest is well :)
http://uk.answers.yahoo.com/question/index?qid=20101012102515AAlORD8 check this out @parthkolhi
OK thanx @ParthKohli :)
@ParthKohli
@anusha.p Haha, I did give a proof for the contrapositive.
Quote, unquote, "I want a direct proof." I told you that we can't just directly prove, and so did Wikipedia. ;P
so..what should i do.......this quest is given under direct proof secton.....:(
Just use my proof. Haha!
Okay, don't get the converse. You start with assuming that \(a = 2k\).\[(2k)^2 =4k^2 = 2(2k)^2 \]
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