Question

For the following problem show how the problem is set up, the work to solve the problem, along with the solution.

A plane travels from Orlando to Denver and back again. On the five-hour trip from Orlando to Denver, the plane has a tailwind of 40 miles per hour. On the return trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip takes six hours. What is the speed of the airplane in still air?

Answer 1

let x = speed of plane in still air
(x+40) = speed of plane downwind
(x-40) =speed of plane against the wind
distance = speed *travel time

downwind distance = headwind distance
5(x+40) = 6(x-40)
5x+200=6x-240
6x-5x=240+200
x=440 mph

The speed of the plane in still air is 440 mph

Answer 2

Is this correct?

Answer 3

yes

Answer 4

i mean the method is right, i did not check the algebra let me check that also

Answer 5

Thank you

Answer 6

yes it is all correct, good work.

Answer 7

Yay (: Thank you!