Question

how many solutions are there to the equation 14x + 2 = 12x

Answer 1

I explained how to solve these problems already

Answer 2

do you know how to solve equations?

Answer 3

what are you not getting about it

Answer 4

if you dont want to learn how to solve problems such as these just type the problem into https://www.wolframalpha.com/i

Answer 5

sorry I mean https://www.wolframalpha.com/

Answer 6

it will give you your answer

Answer 7

still trying to grasp it its been a long time since i took algebra and now i am attending school on-line and it is very challenging!!!

Answer 8

I'm not trying to offend, can you at least make an attempt at the problem?

Answer 9

i am trring a few practice questions

Answer 10

Well the first thing you need to do with these question is isolate the x on one side of the equation and the numbers on the otherside

Answer 11

This is an equality, so what we do to one side we must do to the other or we will lose the equality.

14x + 2 = 12x
Subtract 14x from both sides of the equation
14x + 2 - 14x = 12x - 14x
0 + 2 = -2x
2 = -2x
Divide both sides by -2 because remember -2/-2 = 1 so it will isolate the x

2/-2 = x
2/(2(-1)) = x
1/(-1) = x
-1 = x

Answer 12

\[\frac{2}{-2} = \frac{1}{-1}=\frac{1*-1}{-1*-1} = \frac{-1}{1} = -1\]

Answer 13

14x + 2 = 12x
Subtract 14x from both sides of the equation
14x + 2 - 14x = 12x - 14x
0 + 2 = -2x
2 = -2x
\[\frac{2}{-2} = \frac{-2x}{-2}\]
\[\frac{2}{-2} = x(1)\]
\[\frac{2*(-1)}{-2*(-1)} = x\]
\[\frac{(1)*(-1)}{(-1)*(-1)} = x\]
\[\frac{-1}{1} = x\]
\[-1 = x\]