what is the size of the sample spaces for all the outcomes possible from rolling 6 dice?
36 if you include the order
11 if not
how did you get that?
well, you can roll any of 6 on roll 1, and any of 6 on roll 2 so that's 6 x 6 for part 1
sum of dice can be any from 2..12, that's 11 for part 2
"rolling 6 dice" is appreciably different from adding up the sum of six dice.
oops
OK, start over, sorry.
you guys are confusing mee!!!!
lol plz
But I would say that rolling {1,2,2,4,5,5} is the same as rolling {5,4,2,1,2,5}
im lost :(
sample size is 6
how did you get that @myko
So you can always arrange the six dice in order from lowest to highest, say, and then count all the possible sets of rolls from: {1,1,1,1,1,1} {1,1,1,1,1,2} {1,1,1,1,1,3} {1,1,1,1,1,4} {1,1,1,1,1,5} {1,1,1,1,1,6} .... {1,2,3,4,4,5} {1,2,3,4,4,6} {1,2,3,4,5,5} ... {5,6,6,6,6,6} {6,6,6,6,6,6}
ok?
Sry previous answer got cut. Sample space size is nummber of possible outcomes of an event. So: 6*6*6*6*6*6=6^6 if you count (1,2,3,4,5,6) and (6,5,4,3,2,1) as different outcomes.
okkkk
so im suppose to multiply 6*6
6^6
rolling dice 6 times
which is 36?
@myko ?
\[\large 6^6\]is much bigger than\[\large 6*6\]
\[6^{6}\]
so my answer is 6^6?
yes
kinda confusing lol but ok
|dw:1344982906614:dw| imagine like when you throw a dice you write the result in the table, till complete the 6 cels. So how many different numbers of 6 digits could you get?
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