Quick question! How would I FOIL (3x + 7y)^2? I'm a little confused with the x's and y's...
you write it as (3x+7y)(3x+7y) F first: 3x*3x = ?
3x^2?
remember, math people don't like to type 3x*3x is the same as 3*x*3*x and when you multiply, you can change the order, so it could also be written 3*3*x*x can you simplify it now?
so 9x^2?
yes now O outer: 3x*7y (or for you, 3*x*7*y )
um 21xy? IS that even possible I don't know ):
yes, it is very possible x*y is xy (because xy means x*y) now I inner: 7y*3x (same thing as before)
21xy
and L last: 7y*7y
49y^2
Would I combine them to be 42x^2y^2?
so we have 9x^2 + 21xy + 21xy + 49y^2 the xy terms can be combined: if you factor out xy from (21xy + 21xy)= (21+21)*xy= 42*xy or just 42xy 9x^2 +42xy + 49y^2 or you can say I have 21 xy's (whatever that is) and add 21 more xy's to get 42 xy's
Here is the idea for combining "like terms" a "like term" has exactly the same letters (to the same power) so x^2 matches x^2 but x^2 does NOT match x or x^3 (different powers) and x does NOT match y but xy matches yx (order does not matter) so xy^2 matches xy^2 but not x^2y
If you want more info, maybe this helps http://www.khanacademy.org/math/algebra/polynomials/v/multiplying-binomials
okay, so the answer would just be 3x^2 + 42xy + 49y^2?
I mean 9x^2****
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