Factor the expression 40y^3-8y^2
you can use quadratic formula here if you know how to use the method
Nope im just trying to understand the basic way of factoring this expression and getting the correct answer I think quad is the last part of my term
This is a tricky one. First pull the number that both sets are divisible by. So 8. Then you have to pull a like y term. So y^2. So it becomes something like 8y^2(5y-1)
thank you ill keep working at it
It just takes a WHOLE lot of practice. Factor problems until your hand falls off and then something will magically click. That's what I did and now I can factor pretty much any problem
ok sounds good
The first step will be to look for coefficients and exponents which divide all terms. In this case both terms are even, for example, and have expressions with y in them.
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