a=1/2h(b1+b2) solve for b2. How on earth do I do this?
That appears to be one of those formulas for area. Isolate b2 using legal algebraic steps.
But how?
It matters whether you are talking about 1/2 (h) or 1/(2h). Whichis it?
The first one. 1/2 is a fraction.
There is many ways to go about isolating b2. Here is the path I would take. You do know that multiplying both sides of the equal sign by 2 would still maintain the equality. 2a= h(b1+b2) Did you follow that?
Yes, I understand that. But do I have to distribute now?
Now divide both sides by h. getting (2a)/h = b1 + b2 Still with me?
Yes.. now do i just subtract b1?
I bet you can take it from there.
Yes, and be sure what you take away from one side take away from the other.
so its 2a/h -b1=b2?
As I said you could of worked it many different ways, including distributing the h etc.
I see you remembered, good job.
Alright, thank you so much!
No problem and you are welcome.
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