Simplify.
\[y^2+4y+4/3y^2+5y-2\]
\[\frac{y^2+4y+4}{3y^2+5y-2}\] the only way with would simplify is if the numerator and denominator had common factors, your job is to factor them both, then cancel
the only way i would know how to factor is that the numerator is a perfect square, it is \((y+2)^2\) so your only hope of canceling is if the denominator also has one factor of \((x+2)\) so try to factor \(3y^2+5y-2\) as \((y+2)(\text{something})\)
The furthest i've gotten was to \[2/3y-2\], but none of my answers are like that or any other thing that comes from that.
oh no lets go slow
i am not sure what you did, but you must factor before you can cancel
If you don't mind there's 4 minutes left on the test
okay so factor..got it
lets knock it out \[\frac{y^2+4y+4}{3y^2+5y-2}=\frac{(y+2)(y+2)}{(y+2)(3y-1)}\] now cancel
you got it ?
yeah i got it :) thank you!
yw
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