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Mathematics 26 Online
OpenStudy (rainbow_dash):

Simplify.

OpenStudy (rainbow_dash):

\[y^2+4y+4/3y^2+5y-2\]

OpenStudy (anonymous):

\[\frac{y^2+4y+4}{3y^2+5y-2}\] the only way with would simplify is if the numerator and denominator had common factors, your job is to factor them both, then cancel

OpenStudy (anonymous):

the only way i would know how to factor is that the numerator is a perfect square, it is \((y+2)^2\) so your only hope of canceling is if the denominator also has one factor of \((x+2)\) so try to factor \(3y^2+5y-2\) as \((y+2)(\text{something})\)

OpenStudy (rainbow_dash):

The furthest i've gotten was to \[2/3y-2\], but none of my answers are like that or any other thing that comes from that.

OpenStudy (anonymous):

oh no lets go slow

OpenStudy (anonymous):

i am not sure what you did, but you must factor before you can cancel

OpenStudy (rainbow_dash):

If you don't mind there's 4 minutes left on the test

OpenStudy (rainbow_dash):

okay so factor..got it

OpenStudy (anonymous):

lets knock it out \[\frac{y^2+4y+4}{3y^2+5y-2}=\frac{(y+2)(y+2)}{(y+2)(3y-1)}\] now cancel

OpenStudy (anonymous):

you got it ?

OpenStudy (rainbow_dash):

yeah i got it :) thank you!

OpenStudy (anonymous):

yw

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