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Physics 19 Online
OpenStudy (anonymous):

What is the relationship in which the ratio of the manipulated variable and the responding variable is constant? A. inverse proportion B. direct proportion C. slope D. interdependent

OpenStudy (kainui):

So lets convert this to an equation and find out.\[\frac{ manipulated }{ responding }=constant\]

OpenStudy (kainui):

If we call the manipulated variable x and the responding variable y and the constant c, it just looks like \[\frac{ x }{ y }=c\] So to make a constant what do you have to do to y if you increase x? What do you have to do to y if you decrease x to keep it constant?

OpenStudy (anonymous):

(B)

OpenStudy (shane_b):

Not C :)

OpenStudy (shane_b):

Yes, B

OpenStudy (kainui):

Wrong on both C and B

OpenStudy (anonymous):

sorry but i know it is (B)

OpenStudy (kainui):

You increase x and decrease y to keep a constant or decrease x and increase y to keep a constant. That's not directly proportional.

OpenStudy (anonymous):

buy it is (B)

OpenStudy (kainui):

Lol. You really think so?

OpenStudy (kainui):

If one is increasing and the other is decreasing that is inversely proportional.

OpenStudy (anonymous):

i know so thanks :)

OpenStudy (shane_b):

A real world example - Ohm's Law: V=IR Let R be constant. V is the responding variable I is the manipulated variable. V is DIRECTLY PROPORTIONAL to I (given R is constant). As I goes up, V goes up proportionally.

OpenStudy (shane_b):

Inversely proportional would be something more like this: \[Fg=G\frac{M_1M_2}{r^2}\]Fg is inversely (well, inverse-squared) proportional to the radius r.

OpenStudy (kainui):

lol Yeah I know, I was saying it backwards and confused myself. My bad!

OpenStudy (shane_b):

It happens :)

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