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-15i-15i/1+3i
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is this the question? \[\large{-15i-\frac{-15i}{1+3i}}\] ?
-15-15i/1+3i=?
\[\large{-15i-\frac{15i}{1+3i}}\]
sorry i typed an extra i in the start of the equation
\[\large{\frac{(-15)(1+3i)-15i}{1+3i}}\] First solve this..
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You mean this? : \[\large{-15-\frac{15i}{1+3i}}\]
no as i typed it, i is a complex number or something like that i haven,t studied it yet and thats why i'm, asking.
\[\large{-15i-\frac{15i}{1+3i}}\] \[\large{\frac{(-15i)(1+3i)-15i}{1+3i}}\] try to expand this (simplify)
@sparksaflyen what r u getting?
-6-3i
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I'm sure he/she meant (-15-15i)/(1+3i)
Multiply by the conjugate of base \[\frac{ -15-15i }{ 1+3i }\times \frac{ 1-3i }{ 1-3i }\] Solve
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