What will happen to the spring If I pass the current through it..... ? Please explain ........
spring will contract
NO WAY
Nothing will happen to the spring.
I thin it will act like a solenoid.
*think
when current is passed through spring it acts like a solenoid and initially it will oppose the effect due to current (inductor) but later due to strength of magnetic field spring contracts
WIll contract or no ? I got this view that the spring will experience a force if the magnetic field produced by the current reinforce any external magnetic field..... What do U say...... ? because there is no magnetic field
Ghazi, u r wrong. Lemme explain.
Assuming that the spring is insulated outside and is a conductor, it will act like a solenoid.Refer this if you want to know more about it: http://en.wikipedia.org/wiki/Solenoid
Give me 10 minutes.
@ghazi u are saying that the produced magnetic field due to current will overcome the opposition of the spring...... ?so the spring will contract..... RIght ?
Okay @rajathsbhat ..... I am waiting
right .... see my next comment how and what i want to say and @rajathsbhat i am 100% sure about my answer....see the next comment and read it carefully :)
The basic theory of solenoid valves and their operation is broken down into two components. The first lies in the solenoid coil, which is for all intents and purposes a metal spring. When an electrical current passes through the coil, it becomes an electromagnet and coils in on itself, pulling into a tighter space. The second part of basic solenoid valve theory is in the elastic diaphragm. It prevents fluid from passing because of the balance in fluid pressure between the input portion of the T and the output portion of the T. But when the solenoid coil contracts, it creates marginally more room and the fluid pressure in the output portion of the T decreases slightly. This causes the elastic diaphragm to pull back into the output portion, allowing fluid to pass through the two chambers freely. However, when the electrical current passing through the solenoid coil stops, the coil expands and pushes forward, equalizing the pressure between chambers and sealing them off from one another via the diaphragm. In this way, electromagnetism and fluid pressure become the basics behind the theory of solenoid valve structure and operation.
Assuming the spring isn't already in unstretched condition (i.e., there is some distance between adjacent turns) and is unconstrained, it shortens due to the mutual magnetic attraction between the turns. The force between turns can easily be derived from the force between straight wires (ref.). F = μ0*I^2*L/(2πd), where μ0 is the magnetic permeability = 4pi*1E-7 N/A^2, I is current, L is "wire" length of one turn and d is the distance between turns. Since L = 2πr, where r is the radius of the coils, F = μ0*I^2r/d.
@mathavraj i guess it will be clear now...mutual magnetic attraction!!
@waleed_imtiaz hope it is clear now...
Now @gazhi don't copy and paste answers hoping to get more medals. http://answers.yahoo.com/question/index?qid=20090322164348AARf8XT Source where he copied his answer from.
i ain't copying i just wanted to make @rajathsbhat clear...i am here for discussion not for medals @kartiksriramk ....if you can't help ..then better not to make any unfavorable comment..please!!
@kartiksriramk i knew these answers ..but it would have taken time to write these stuff so i just brought content over here to save time....
i will research this thoroughly & perform the experiment myself before posting anything. But my initial suspicion is that ghazi is right....
@ghazi so u are saying that when current will pass through the spring , it will act like an electromagnet and it will coil around itself.......So, it will contract...... RIght ? If this is true then Em okay...... with ur answer.......
yes...@waleed_imtiaz it will contract and the detailed reasoning is in front of you :)
OKay Fine......... Thanks
welcome :)
@mathavraj sorry dude..by mistake i mentioned your name... my apology :)
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