1+11+111+1111+11111.... the geometric series can be summed to infinity. Find this sum
this will be diverge but only thing we can do is to find sum of \(n\) term
But this isn't a geometric series to start with, is it?
Hint:Multiply divide by 9
and also this not a GP
how do you find the sum of the n term
Guys this isn't GP! We have to convert it into GP! For this: Multiply Divide by 9: 9+99+999+9999+99999..../9 Now we can write 9 as 10-1 and 99 as 100-1 ...and so on..So now this is GP . Now use the infinite sum formula: S=a(r^n-1)/r-1 You have the answer :)
thanks!
I think the sum of the first n terms is \[\sum_{k=0}^{n}(n-k)10^{k}\]
I don't think what @DLS did actually made it into a Geometric Series... Unless I'm missing something If I am, please enlighten me :(
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