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Mathematics 21 Online
OpenStudy (anonymous):

1+11+111+1111+11111.... the geometric series can be summed to infinity. Find this sum

OpenStudy (anonymous):

this will be diverge but only thing we can do is to find sum of \(n\) term

terenzreignz (terenzreignz):

But this isn't a geometric series to start with, is it?

OpenStudy (dls):

Hint:Multiply divide by 9

OpenStudy (anonymous):

and also this not a GP

OpenStudy (anonymous):

how do you find the sum of the n term

OpenStudy (dls):

Guys this isn't GP! We have to convert it into GP! For this: Multiply Divide by 9: 9+99+999+9999+99999..../9 Now we can write 9 as 10-1 and 99 as 100-1 ...and so on..So now this is GP . Now use the infinite sum formula: S=a(r^n-1)/r-1 You have the answer :)

OpenStudy (anonymous):

thanks!

terenzreignz (terenzreignz):

I think the sum of the first n terms is \[\sum_{k=0}^{n}(n-k)10^{k}\]

terenzreignz (terenzreignz):

I don't think what @DLS did actually made it into a Geometric Series... Unless I'm missing something If I am, please enlighten me :(

OpenStudy (anonymous):

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