Factor: 4x2 + 12x + 9
check to see if there is a gcf in this case its 1
you just look at the factors of 4 and 9 and see if any combination of them will get you 12
4 and 3 will get me 12 but 9 is prime so what do I do now ?
so you would use the Ac method or Decomposition a=4x^2,c=9 36 what number adds up to 12 and when multiplied =36 in this case its 6 and 6 so it would be like this (4x^2+6x) ( 6x+9) 2x(2x+3) 3(2x+3)
my bad sorry mistake
Actually, you can use the identity \((a+b)^2 = a^2 + 2ab+b^2\) to do it. 4x^2 + 12x + 9 = (2x)^2 + 2(2x)(3) + 3^2 = ...?
can any1 answer my questions
@RolyPoly its only true in this case
Yes. But if it is applicable in this case, why not use this identity?
im trying to finsih already this is the last test for me
Factor: 4x^2 + 12x + 9 A (2x + 3)2 B (4x + 9)(x + 1) C (2x + 1)(2x + 9) D (2x + 3)(2x - 3)
@SPC Which part you don't understand?
I dont understand how you got your answer.
A
How to Factor step by step: x^2 - 28x + 75 A (x - 14)(x - 14) B (x - 5)(x - 15) C (x - 3)(x - 25)
4x^2 + 12x + 9 Consider the first term, 4x^2 = \(2^2x^2\) = \((2x)^2\) Consider the second term, 12x = 2(2x)(3) Consider the last term, 9 = 3^2 Now, think about the identity for perfect square, \((a+b)^2 = a^2 + 2ab+b^2\) Match the corresponding a and b to get your answer.
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