Question

Help me find the differential dy given y=(√3x^2-4), then dy = a. 6x(√3x^2-4)dx b. (3x)/(√3x^2-4)dx c. (6x)/(√3x^2-4) d.
2(√3x^2-4)/(3x)dx

Answer 1

is that seperate questions? im not understanding it..

Answer 2

it goes from a , b , c , d? :/

Answer 3

@Omniscience i think they are answer choices

Answer 4

multiple choice? the asker should confirm..

Answer 5

yes they are. bleh

Answer 6

can you please write it properly? :)

Answer 7

yea just give me a sec

Answer 8

hint* use chain rule

Answer 9

a) \[6x \sqrt{3x^2-4}dx\]
b)\[3x/\sqrt{3x^2-4}dx\]
c)\[6x/\sqrt{3x^2-4}dx\]
d)\[2\sqrt{3x^2-4}/3x dx\]

Answer 10

F'(x) = f '(g(x)) g '(x) => chain rule so if we apply it....