Help me find the differential dy given y=(√3x^2-4), then dy = a. 6x(√3x^2-4)dx b. (3x)/(√3x^2-4)dx c. (6x)/(√3x^2-4) d.
2(√3x^2-4)/(3x)dx

Question

Help me find the differential dy given y=(√3x^2-4), then dy = a. 6x(√3x^2-4)dx  b.  (3x)/(√3x^2-4)dx c. (6x)/(√3x^2-4)    d. 
2(√3x^2-4)/(3x)dx

anonymous · Answer

is that seperate questions? im not understanding it..

anonymous · Answer

it goes from a , b , c , d? :/

alexwee123 · Answer

@Omniscience i think they are answer choices

anonymous · Answer

multiple choice? the asker should confirm..

anonymous · Answer

yes they are. bleh

anonymous · Answer

can you please write it properly? :)

anonymous · Answer

yea just give me a sec

alexwee123 · Answer

hint* use chain rule

anonymous · Answer

a) $$6x \sqrt{3x^2-4}dx$$
b)$$3x/\sqrt{3x^2-4}dx$$
c)$$6x/\sqrt{3x^2-4}dx$$
d)$$2\sqrt{3x^2-4}/3x  dx$$

alexwee123 · Answer

F'(x) = f '(g(x)) g '(x) => chain rule so if we apply it....
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