Question

Verify the identity. 1-cos^2x=TanxCosxSinx

Answer 1

got it?

Answer 2

@sauravshakya direct answer dude.. please let the user do it by him/her selft

Answer 3

*self

Answer 4

SORRY.........

Answer 5

MY mistake

Answer 6

No problem but remember this from now on wards

Answer 7

Don't forget he is an Ambassador..

Answer 8

....yeahh

Answer 9

1-cos^2 x =sin^2 x

Answer 10

No no water.. He is my friend that is why I hoped that I had been polite rather been a rude person. ?

Answer 11

*hope

Answer 12

You took it seriously I am just kidding...

Answer 13

okay yes I got that part. 1-cos^2x = sin^2x

Answer 14

ya... we r friends..

Answer 15

now, sin^2 = sinx * sinx

Answer 16

right?

Answer 17

missing x on left..

Answer 18

yeess

Answer 19

oh ya.... thanx @waterineyes

Answer 20

Now, sinx * sinx * cosx/cosx

Answer 21

right?

Answer 22

He just multiplied and divide by cos(x)..

Answer 23

where did you get the cosx/cosx from ?

Answer 24

\[\sin(x) \cdot \sin(x) \times \frac{\cos(x)}{\cos(x)}\]

Answer 25

tanxsinxcosx
= (sinx/cosx) sinxcosx
= sinx * sinx * cosx / cosx

Answer 26

For the right side.

Answer 27

@Callisto I am also thinking the same that now we should simplify right hand side to prove..

Answer 28

he used the identity tanx = sinx/cosx

Answer 29

So, then I am leaving....

Answer 30

Actually if we want to just prove by using left hand side then @sauravshakya is going right...

Answer 31

Uh-oh. I'm sorry....

Answer 32

Carry on @sauravshakya

Answer 33

okay so far I have sinx.sinx= sinx/cosx cosx.sinx now what do I do ?

Answer 34

Use this :

\[\frac{\sin(x)}{\cos(x)} = \tan(x)\]

Answer 35

alright. so tanx=tanx right ?

Answer 36

I mean to say that use this identity there...

Answer 37

Check for colored part:

\[\color{blue}{\frac{\sin(x)}{\cos(x)}} \cdot \sin(x) \cdot \cos(x)\]

Answer 38

Can you replace that colored part ?

Answer 39

u 1/cscx / 1/secx ?

Answer 40

see you have:

\[\color{blue}{\frac{\sin(x)}{\cos(x)}} \cdot \sin(x) \cdot \cos(x)\]

And there is one formula which says that:

\[\frac{\sin(x)}{\cos(x)} = \tan(x)\]

Can you use this formula above ??

Answer 41

umm no im kind of confused

Answer 42

What is blue colored part can you write here ??

Answer 43

Only write the part that I have shown you in blue color..

Answer 44

sinx/cosx would be tanx

Answer 45

yes..

Answer 46

so just repalce it here:

\[\color{blue}{\frac{\sin(x)}{\cos(x)}} \cdot \sin(x) \cdot \cos(x)\]

Answer 47

only change the blue colored part with what you just said above..

Answer 48

tanx.sinx.cosx. okay than what ?

Answer 49

You want to do more in this ??

Answer 50

do i have to or is that it?

Answer 51

With your big eyeballs, see the right hand side of your question..

Answer 52

LOL okay nvm thank you ! :)

Answer 53

Ha ha ha..

Just kidding..

Welcome dear...

Answer 54

Thanks to @sauravshakya and @Callisto too...