Question

How do you solve x^2-13x+36

Answer 1

So far I have
x^2=x
36 is 62ab=2(x)(6)=12x
It doesnt give me 13x

Answer 2

you can factor this
you need two numbers whose product is + 36 and whose sum is -13

Answer 3

or you could do the quadratic formula?

Answer 4

What is that

Answer 5

it factors to binomials:
(x )(x )
where 2 numbers go into blanks

Answer 6

\[x=\frac{ -b \pm \sqrt{b^2 -4ac} }{ 2a }\]
Where a, b and c are the coefficients in the quadratic (here a=1, b=-13 and c = 36)
So if you put these numbers in you will get x=9 and x=4.

Answer 7

(x-4)(x-9)

Answer 8

think of factors of + 36
4 and 9
you need -13
so its -4 and -9

factors are
(x - 4)(x - 9)

Answer 9

then from there you just solve for 0

Answer 10

so it would be 4 and 9

Answer 11

yep (:

Answer 12

if you have equation x^2 - 13x + 36 = 0
the roots are 4 and 9

Answer 13

when you ask to solve it usually means solve an equation
so you should have written it as an equation
that is
x^2 - 13x + 36 = 0