Let f(x)= sinx/x a.) What is the average rate of change of f on the interval [π/2, 3π/2]? b.) What is lim f(x) as x approaches 0? c.)Is the line x=0 a vertical asymptote of f? Justify your answer using limits. d.) Use the Squeeze Theorem to show the one y=0 is a horizontal asymptote of f.
average rate of change of f(x) in the interval (a,b) is: f(b)-f(a)/b-a
How do I know what f (π/2) is though?
f(π/2) = sin π/2/π/2 = ?
1/π/2
Sorry, I'm missing my calculator right now -.-
right: 2/π
Ah, yes.
do the same for the other point
-2/3π?
For sin(3π/2)/(3π/2)
OH wait.... 3π/2 isn't even on the unit circle.
it's the angle
yeh it is, never mind...
Yes, -2/3π
f(3π/2) =-2/3π
now do the ratio f(b)-f(a)/b-a
Okay hold on.
-7/2
(-2/3π - 2/π)/(3π/2-π/2)=-8/3π/π=-8/3
sigh... Okay :(
The limit as X approaches 0 would be 1 correct?
yes
X=0 is not a vertical asymptote is it?
right
How can I justify that using limits?
Because x approached infinity from both sides?
infinity and negative infinity that is.
no, lim f(x) for x->0 is 1, remmeber
Yeh but how does that prove that x=0 is not a vertical asymptom?
asymptote*
when a lione is asymptot, the graph should stay in one of its sides, but in this case it is not true
OKay!
Can you give me a brief easy ideal of the "squeeze Theorem". i didn't really understand it in class.
imagine 3 functions: f(x), g(x) and h(x) that have this property: f(x)< g(x) < h(x) when x->a limits of f(x) and g(x) are for example = b , so this will be also the limit of g(x)
Hmmm... okay, so how can I use this Theorem to show that y=0 is a horizontal asymptote of f?
http://www.wolframalpha.com/input/?i=f%28x%29%3D+sinx%2Fx i don't think y=0 is a horizontal asymptot
So it would appear. Very interesting. Perhaps the worksheet has made an error. Regardless, thanks for your help!
you wellcome
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