3^5 / (-3)^7 ... I believe that makes the base 0, right? So then what happens with the exponents? Help please!
When dividing exponential expressions with the same base, you subtract the corresponding exponents.
So you first need to make sure that the bases are the same
Notice how (-3)^7 = (-1*3)^7 (-3)^7 = (-1)^7*(3)^7 (-3)^7 = -(3)^7
But they aren't, so now I am confused what I do instead. This is just one part of the question
I need someone to step by step explain what they are doing when they move all these numbers around and such, because I am not undetstanding by just looking at it
So 3^5/(-3)^7 is the same as 3^5/( -(3)^7 ) which simplifies to - 3^5/3^7
Do you see how I'm getting all this?
I'm not because it's just numbers, I need it explained in english word by word step by step because just analyzing it confuses me even more. I need to verbally know what im doing so i can talk myself through the question
alright
In going from (-3)^7 to (-1*3)^7, I'm factoring -3 into -1 times 3
So (-3)^7 = (-1*3)^7
From there, I'm raising everything inside the parenthesis to the 7th power like so (-3)^7 = (-1)^7*(3)^7
Why are you doing that, where is that -1 coming from, why did you move the -3 to positive exponent?
Because I want to extract out the 3 (since the first base is a 3)
but the second is a -3, so we can say -3 = -1 times 3
so just mentally you thought of that? is there something that tells you to do that?
mentally I did (just because I've been doing this a while), but you can divide the first base (3) by the second base (-3) to get 3/(-3) = -1 So you need to factor out a negative one from the second number to get the first number
Let me explain the full question. It is long, and I'm just focussing ONE of four parts so doing this will take all day it seens? i am not understanding
alright
okay so always divide first base by second base? and use that number always? if there are uneven anyway?
not counting if they are the same as that is a much simpler formula
well in this case, it works out evenly...but it won't always give you an integer
i wish i could actually speak to someone on the phone or something, typing is so hard to explain everything
i understand, but you're doing great...you just have to keep at it
you can take a screenshot of it to save typing
i am taking an online class and this is honestly the hardest thing of my life. hardest thing i have EVER done or lack there of i guess you ccan say since i cant do anything :/
I'm sure you're doing fine. You just have to take things one step at a time.
and don't be so hard on yourself, I'm sure you can do lots of things well
It is not letting me attach the picture. can we try to email? can i do that on this site?
hmm maybe you can post the pic on a 3rd party site (like photobucket) and link it in
i am trying
http://a2.sphotos.ak.fbcdn.net/hphotos-ak-snc7/394505_10152043452630624_648218901_n.jpg
as i said, it is just one part of the equation but i want to focus on just it so i dont get any more confused than i already am
ok I see it now, one sec
you agree that you can factor -3 into -1 times 3 right?
yes that makes sense
so why not factor -3 into -1 times 3 so in step 2, rewrite everything in step 1, but instead of writing -3, write -1 times 3
But I did step two, the second line. is that wrong?
then raise every factor to their corresponding exponent
no, it's not wrong
The main question is the top top line. secondf line is what i did
I'm just breaking it down further
I dont understand how you want me to do that with everything else around it. what am i doing?
let me draw it out, one second
We have the following problem \[\Large \frac{\left( 3x^4y^5z^7\right )^{5}}{\left(-3x^3yz^4 \right )^{7}}\] correct?
yes, that is the original question and i broke it down further and did one other step, the second line on the picture i sent you
and frokm what i understand, that was right. now you are talking to me about the third step and that is where i am getting vconfused
here's what I mean in step 2
\[\Large \frac{\left( 3x^4y^5z^7\right )^{5}}{\left(-3x^3yz^4 \right )^{7}}\] \[\Large \frac{\left( 3x^4y^5z^7\right )^{5}}{\left(-1*3x^3yz^4 \right )^{7}}\]
step 3 is then...
so what you are saying isw that before i do anything else, i should try to get the bases the same, then go forth, right?
\[\Large \frac{\left( 3x^4y^5z^7\right )^{5}}{\left(-3x^3yz^4 \right )^{7}}\] \[\Large \frac{\left( 3x^4y^5z^7\right )^{5}}{\left(-1*3x^3yz^4 \right )^{7}}\] \[\Large \frac{\left( 3\right)^{5}\left(x^4\right)^{5}\left(y^5\right)^{5}\left(z^7\right )^{5}}{\left(-1\right )^{7}*\left(3\right )^{7}\left(x^3\right )^{7}\left(y\right )^{7}\left(z^4 \right )^{7}}\]
Do you see where to go from here?
So let me try to do this but it will be wrong i am assuming so can you help explain why it is wrong?
alright, go for it
let me ask you something first
whats that
should i just be solving each line as it's own not even acting as if the other exists right niow? until i break it down firther?
like 3 to the power of five is 243. is that what i should be doing?
that's a good way to do it, taking it one step at a time (and not focusing on the other steps) will simplify things greatly
you can have that off to the side
3^5 = 243 (-1)^7 = -1 etc etc
once you have all the pieces, you can put them together to form a complete step
i should leave that for now and simplify the other ones with the exponents in brackets and exponents out of brackets, right? before i do anything else
this will avoid generating a million steps
you can think of \[\Large \left( 3\right)^{5}\] as \[\Large \left( 3^{1}\right)^{5}\]
since 3^1 = 3
so you can then multiply each outer exponent with the corresponding inner exponent (for each term)
k but what im sayign is that one is already simplifed to the next level i guess you could call it so i should make the other ones with just one exponent like it is, right? sorry i make no sense. i am the dumbest person ever
no you're not, don't even think that
yes that is what i am saying. i think. okay hang on
yes go ahead and do what you're describing and I'll tell you if you did it correctly or not
okay i have a feeling the bottom line is wrong but i did my best.
show me what you got
http://a7.sphotos.ak.fbcdn.net/hphotos-ak-ash4/488369_10152043559615624_302584141_n.jpg
alright, let me have a look
how did you get 3^42 ?
the 42 is wrong ... 49 instead? forgot how to count lol
or maybe just leave at 3^7?
Yes just 3^7 or 2187
Since 3^7 = 2187
okay now can you explain why so i remember? because it is confusing me
\[\Large (3)^7 = \left(3^1\right)^7\] agreed?
okay see i feel we should keep it at the first step because i didnt know that wheni wads doing the rest of the equation
you mean keep it (3)^7 ?
well like it is not being timsed by sseven like all the rest, so i need to remember that or i will always screw it up you kinow?
ah i see what you mean
you just have to remember that there's a 1 up there (by default)
i cant explain it, thats not what i mean. i dont know how to say it
if there is no exponent
hmm alright, but just keep that in mind
i dont understand what you said. even more confusion. you dont have to help mne if this is too much for you
I'm sorry, I didn't mean to confuse you further
I just want to keep that 1 there so i know, because if not i am doing something i should not be doing it seems
alright
anyway, now that i have that step, with the number changed from 42 to a simple 7, i am trying to figure out what to do next
your next step is to divide and simplify
how do i divide like this? i dont really divide, i add right? or no, subtract actually
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