Question

add & simplify 2x+6/(x+3)^2 + x/x+3.
a: 3x+6/(x+3)^2
b: x+2/x+3
c: x+2/(x+3)^2
d: 2/3

Answer 1

multiply 2x+6 with x+3 which yields 2x^2+12x+18

\[(x+3)^2 = x^2+6x+9\]

multiply x with second equation will give you

\[x^3+6x^2+9x\]

add 2x^2+12x+18 and \[x^3+6x^2+9x\]

this gives you numerator

keep \[x^3+6x^2+9x\] and x+3 as it is in the denominator

Answer 2

simplify the numerator and a term will cancel out with denominator