Question

What are the values that satisfy the trigonometric equation for 0 £ q < 2p?

Answer 1

\(0\leq \theta <2\pi\) i hope

Answer 2

sin(x) + tan(-x) = 0

sin(x) - tan(x) = 0 ... since tan(x) is an odd function

sin(x) - sin(x)/cos(x) = 0 ... using the idea that tan(x) = sin(x)/cos(x)

sin(x)cos(x)/cos(x) - sin(x)/cos(x) = 0 ... Multiply the first fraction by cos(x)/cos(x)


( sin(x)cos(x) - sin(x) )/cos(x) = 0 ... Combine the fractions

With me so far?

Answer 3

btw, I'm using x instead of theta (since it's easier to type x)

Answer 4

Okay...

Answer 5

Satellite73. It says what i posted on the question

Answer 6

so

sin(x)cos(x) - sin(x) = 0

sin(x)(cos(x) - 1) = 0

sin(x) = 0 or cos(x) - 1 = 0

sin(x) = 0 or cos(x) = 1

x = arcsin(0) or x = arccos(1)

x = 0 or x = pi, x = 0 or x = 2pi (use the unit circle here)

So the solutions are x = 0 or x = pi

We toss out x = 2pi because it's not in the given interval

Answer 7

Hmmm. Okay. Thank you

Answer 8

any questions?

Answer 9

it says 0 £ q < 2p ??

Answer 10

I think you explained pretty good. And yeah. Thats what it says on my question. idk what its suppose to really mean

Answer 11

yeah, my guess it's a serious glitch and it should be \[\Large 0 \le x < 2\pi\]

Answer 12

it means it was coded incorrectly or your browser is reading it wrong