If a = -12/5, then 5x + 2y = 6 and 3x - ay = 4 are parallel.
ok so first of all : \[\large{5x+2y=6}\] \[\large{5x=6-2y}\] \[\large{x=\frac{6-2y}{5}}\] right?
@jordan1919 please reply
ohh yea ok
now put this value in the equation 3x-ay=4
it doesn't need to be solved i need to figure out hot to determine if they are parallel or not.
oh sorry
no its fine.
why not to find x intercept and y intercepts first?
idk y the question is jus if it is parallel true or false i can't really understand what it's asking.
ok let us try to first find x intercept what do you get?
Firstly put a = -12/5 in the equation.. and then solve the equation..
\[3x - \frac{-12}{5}y = 4 \implies 15x + 12y = 20\]
You other equation is : \[5x + 2y = 6\]
Find their slopes if they are equal then lines must be parallel.. For first one: Slope = \(\frac{-x \; coefficient}{y \; \; colefficient} = \frac{-15}{12} = \frac{-5}{4}\)
For second one: Slope : \(\frac{-5}{2}\) As they are not equal so the line equations are not parallel..
ohh thank for explaining like that it made it very easy to understand.
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