Question

What are the zeros of the polynomial function: f(x) = x^3 – 5x^2 + 6x

Answer 1

first take out x:
f(x) = x(x^2 - 5x + 6) = 0
(x(x - 3)(x - 2) = 0
can you continue?

Answer 2

i still do no understand

Answer 3

not*

Answer 4

did you understand why i took the x out?

Answer 5

no :(

Answer 6

0, –3, 2

0, 3, –2

0, –3, –2

0, 3, 2
I got these four answers

Answer 7

do you understand why there's three answers?

Answer 8

yes but i dont know which one is correct, i tried four different times and ended up with these ugh

Answer 9

The zeroes is just where y = 0. So pretend f(x) is your y and plug in 0.
0 = x^3 – 5x^2 + 6x
Do you know how to solve this? Just ignore f(x)

Answer 10

I would start by factoring first, all of these numbers have a common factor, x.
x (x^2 - 5x + 6)
Now, factor it further by factoring x^2-5x+6
You get (x-3)(x-2)
you're left with x(x-3)(x-2)
Equal each of these expressions to zero.

x=0
x - 3 = 0, which is x=3
x - 2 = 0, which is x =2