Use an appropriate Riemann sum to evaluate the limit (see attached).

Question

anonymous · Answer

attachment

anonymous · Answer

Well your limit has x->infty but only mentions the variable n...

anonymous · Answer

oh that was a typo on my part

anonymous · Answer

n-->infinity .  and it's what the problem requires...

anonymous · Answer

Here is a similar problem if it helps: 
steps are shown

anonymous · Answer

Because any exponent in the denominator that is greater than the highest degree exponent in the numerator is zero

anonymous · Answer

Yes, it's pretty retarded

anonymous · Answer

I wrote that wrong but you know what I mean

anonymous · Answer

I guess they're trying to drive the point home that a reimann sum with infinite rectangles is an integral...

anonymous · Answer

Nvm what I said earlier.  The sums are infinite, so they don't easily cancel out.

anonymous · Answer

I think I'll just be like "Textbook is stupid. Answer is zero"... too much work