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Mathematics 14 Online
OpenStudy (anonymous):

Simple probability question; Attachment below.

OpenStudy (anonymous):

OpenStudy (anonymous):

it really is simple after you figure out what \(P(4)\) is, because then you multiply the result by \(600\)

OpenStudy (anonymous):

the question really comes down to finding \(P(4)\) any ideas, or you want a hint

OpenStudy (anonymous):

Hint please..

OpenStudy (anonymous):

the total probability is 1 you have already used up \(\frac{3}{4}\) of it on \(P(1), P(2), P(3)\) how much is left?

OpenStudy (anonymous):

1/4 is left for the other three, so that means that I would have to find 1/4 of 600 then divide it by 3 to get the Pr(4)?

OpenStudy (anonymous):

that is one way to look at it, yes

OpenStudy (anonymous):

i would have said what is left is \(\frac{1}{4}\) and since the other three are equally likely they must each be \(\frac{1}{12}\) but it amounts to the same thing, i.e. you will get the same answer in either case

OpenStudy (anonymous):

Thanks for your help @satellite73 :D

OpenStudy (anonymous):

yw

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