Question

I have no idea where to begin. :l Helpp?

In Triangle ABC shown below, side AB is 6 and side AC is 4.



Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Segment AD is 3 and segment AE is 4.

Segment AD is 3 and segment AE is 2.

Segment AD is 12 and segment AE is 8.

Segment AD is 12 and segment AE is 4.

http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1000_Subtest_01_01/image0014e8c4ab2.jpg

Answer 1

for half length side must be in proportion so...can you guess now?

Answer 2

Segment AD is 3 and segment AE is 2.

Answer 3

Understood @tiffybabyy ??
or any doubt ??

Answer 4

So I would do this??
\[\frac{ 6 }{ 4 }=\frac{3}{ 2 }\]
Cross multiple and if they equal out then its right?

Answer 5

yes

Answer 6

so the answer will be "Segment AD is 3 and segment AE is 2." isnt it @TheViper ???

Answer 7

Okay(: Thank you guys !!

Answer 8

my pleasure and thanks viper :)

Answer 9

\[\frac{ AD }{ AB }=\frac{ AE }{ AC }\]

Answer 10

If this is a triangle (of any type) :-& if \(\Large{AD=BD}\)& \(\Large{AE=EC}\)then \[\Large{DE \parallel BC}\]


So answer is Segment AD is 3 and segment AE is 2.

Answer 11

@ghazi @annas @tiffybabyy now it's clear??

Answer 12

Yeah. I get it. Thanks you guys! :D

Answer 13

hmmm...... Ur welcome ;)

Answer 14

yeah i got it :) thanks viper dude

Answer 15

dude I like saying dude !!

Answer 16

lol me too dude :P