Question

complexnumbers

Answer 1

for the polar form you've got to find theta ...find it by using tan theta = (-b/a)

Answer 2

\[\tan \theta = (-(1/2)/\sqrt{3}/2)\] can you find theta now?

Answer 3

arctan of (-1/2/rt3/3)...

Answer 4

see theta= 30 degrees

Answer 5

nope sorry theta= 120 degrees

Answer 6

-30 from horizontal?

Answer 7

yes...exactly

Answer 8

now you can write it in polar form \[r(\cos \theta +i \sin \theta)\]

Answer 9

to find r use \[r=\sqrt{(\sqrt{3}/2)^2+ (1/2)^2}\]

Answer 10

now i hope you can do it

Answer 11

i know how to get the magnitude..what is principal argument mean?

Answer 12

principal argument is the value in between \[-\pi,\pi\]

Answer 13

since there can be many value if checked around 360 degrees on a complex plane...so you've to use the value between (-pi,pi)

Answer 14

not 0 and 2i?

Answer 15

i guess no

Answer 16

some authors use close interval 0 to open interval 2 pi but ...you should use between -pi to pi for the principal values :)

Answer 17

tks