Question

Given the linear equation y=-2/3x+1, find the y-coordinates of the points (-6, ), (-3, ), and (3, ). Please show all of your work.

Answer 1

so you have
x = -6
x = -3
x = 3

plug and chug

Answer 2

remember a point is

(x,y)
you have

(-6, y)
(-3, y)
(3, y)

Answer 3

plug the numbers in as x and solve for y

Answer 4

Y=-2/3x+1
Y=-2/3*-6+1
Y=5
Y=-2/3*-3+1
Y=3
Y=-2/3*3+1
Y=-1
(-6,5)(-3,3)(3,-1)

Answer 5

for x = -6
y = 2/(3(-6) + 1)
y = 2/((-18) + 1)
y = 2/-17
y = -2/17

Answer 6

wait is the question

\[y = \frac{-2}{3x+1} \]
or
\[ y = \frac{-2}{3x} + 1\]

Answer 7

and I made a mistake my answer should have been

y = 2/17

Answer 8

if it is the first case

Answer 9

I guess I should have assumed it was the second case since there is a lack of brackets

Answer 10

y = -2/-18 + 1
y = 2/18 + 18/18
y = 20/18
y = 10/9

Answer 11

that is the solution for the second way your question can be interpreted, I dont know how you got 5 as a solution for x=-6

Answer 12

Recall that the question mentioned that it was a linear equation :)

Answer 13

blah my reading comprehension is shot so burned out by school :)

so it is really

\[y = \frac{-2}{3}x + 1\]

Answer 14

y = -2*-6/3 + 1
y = 12/3 + 1
y = 5

alright yeah you are right good job :)

Answer 15

thank you, i was starting to get a little confused lol. sometimes the numbers start running together in my head so i like to get on here and check my work

Answer 16

try

https://www.wolframalpha.com

Answer 17

it is a great site for checking your work

Answer 18

thank you