Evaluate this integral: \[ \large \int_0^\infty\frac1{x^x}dx \]
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\[\large \int_0^\infty\frac1{x^x}dx\]learn latex!
yeah i know ... draw is just too quicker.
I doubt you can define it. The lower bound is an essential singularity.
@experimentX can u solve this.
no not really ... i was expecting it's answer to be in infinite series ... http://openstudy.com/users/leksi#/updates/4ff409aee4b01c7be8c7845f but Mathematica refused to give it's answer. http://www.wolframalpha.com/input/?i=integrate+1%2Fx^x+from+0+to+infinity
Huh, interesting. Well, I would take a look in Gradshteyn and Ryzhik. If it can be defined at all, even as a series, it will be there.
i hope so!!
santosh just like that integral \[ \int_0^\infty\frac1{x^x}dx=\sum_{n=0}^{\infty} \frac{(-1)^n}{n!} \int_{-\infty}^{\infty} t^n e^{(n+1)t} dt\]
but the later integral part diverges
yep ... this isn't analytic :((
try it with mathematica...in terms of n and t
Hmm, if you plot the integrand it seems perfectly well-behaved over the entire domain.
@Carl_Pham it converges ... @mukushla that's one hell of crazy structure :(((
@experimentX please tell me how |dw:1345409192350:dw|
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