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Mathematics 20 Online
OpenStudy (anonymous):

What is the sum of a 6–term geometric series if the first term is 6 and the last term is 1,000,842? 188,851 157,962 138,073 117,648

hartnn (hartnn):

do u know the formula for 'n' th term of geometric sequence?

OpenStudy (anonymous):

Nope

hartnn (hartnn):

its Tn=a*R^(n-1) a is 1st term given as 6 R is common ratio n=6 as number of terms is 6 so can u find R from this?

OpenStudy (anonymous):

So I plug it in and get Tn=a*R^(6-1)?

hartnn (hartnn):

the 6th term given to u =T6=1000842 now u have T6,n,a...find R from the formula

OpenStudy (anonymous):

So it would be 138,073?

hartnn (hartnn):

no R will be 11.077 then u put formula for sum of GP which is a(R^n-1)/(R-1)

OpenStudy (anonymous):

Nooo, I knew the second formula, I was saying the final answer is 138,073?

hartnn (hartnn):

i think the options or question is incorrect,because if last term is 1000842,how come the sum is less than it?

hartnn (hartnn):

did u put an extra 0?

OpenStudy (anonymous):

Nope, the question is correct,I just checked again.

hartnn (hartnn):

no its 100842 only,because then R=7

hartnn (hartnn):

and your sum is 117648

OpenStudy (anonymous):

THANK YOU!

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