What is the sum of a 6–term geometric series if the first term is 6 and the last term is 1,000,842? 188,851 157,962 138,073 117,648
do u know the formula for 'n' th term of geometric sequence?
Nope
its Tn=a*R^(n-1) a is 1st term given as 6 R is common ratio n=6 as number of terms is 6 so can u find R from this?
So I plug it in and get Tn=a*R^(6-1)?
the 6th term given to u =T6=1000842 now u have T6,n,a...find R from the formula
So it would be 138,073?
no R will be 11.077 then u put formula for sum of GP which is a(R^n-1)/(R-1)
Nooo, I knew the second formula, I was saying the final answer is 138,073?
i think the options or question is incorrect,because if last term is 1000842,how come the sum is less than it?
did u put an extra 0?
Nope, the question is correct,I just checked again.
no its 100842 only,because then R=7
and your sum is 117648
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