Mathematics
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OpenStudy (anonymous):
How many times as intense as a standard earthquake is a earthquake measuring 3.1 on the richter scale?
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OpenStudy (anonymous):
what is the intensidy of a standard earthquake?
hero (hero):
I'm pretty sure you have the formula for this somewhere.
OpenStudy (anonymous):
i havent been given any formuals other than basic ones
OpenStudy (anonymous):
R = log[ I ÷ I0 ]
OpenStudy (anonymous):
M=log I/S
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jimthompson5910 (jim_thompson5910):
Hint: Solve for I (capital i)
jimthompson5910 (jim_thompson5910):
After that, plug in M = 3.1
jimthompson5910 (jim_thompson5910):
Keep in mind that \[\Large I_{0}\] is the "standard earthquake"
OpenStudy (anonymous):
so if i solve for I what do i start with?
jimthompson5910 (jim_thompson5910):
well the intensity of it anyway
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jimthompson5910 (jim_thompson5910):
I would convert the given equation to exponential form
jimthompson5910 (jim_thompson5910):
to start things off
OpenStudy (anonymous):
i was gunna start with m=log 3.1/s
jimthompson5910 (jim_thompson5910):
no, m = 3.1 since m is the magnitude
OpenStudy (anonymous):
3.1=log I/S
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jimthompson5910 (jim_thompson5910):
yes
jimthompson5910 (jim_thompson5910):
now convert to exponential form
OpenStudy (anonymous):
i dont know how to do that
jimthompson5910 (jim_thompson5910):
Use the idea that
\[\Large \log_{b}(x) = y\]
is the same as
\[\Large b^y = x\]
OpenStudy (anonymous):
i still dont understand
im left with log I/S correct
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OpenStudy (anonymous):
and log is to the base 10
jimthompson5910 (jim_thompson5910):
When you convert
\[\Large 3.1 = \log\left(\frac{I}{S}\right)\]
to logarithmic form, you get
\[\Large 10^{3.1} = \frac{I}{S}\]
jimthompson5910 (jim_thompson5910):
Now solve for i
OpenStudy (anonymous):
10^3.1 becomes 1258
jimthompson5910 (jim_thompson5910):
1258.92541179417
but you pretty much have it
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OpenStudy (anonymous):
ok so do i bring over the I or what?
jimthompson5910 (jim_thompson5910):
\[\Large 3.1 = \log\left(\frac{I}{S}\right)\]
\[\Large 10^{3.1} = \frac{I}{S}\]
\[\Large 1258.92541 = \frac{I}{S}\]
jimthompson5910 (jim_thompson5910):
now isolate 'i'
jimthompson5910 (jim_thompson5910):
by moving that 's' over
OpenStudy (anonymous):
so it becomes 1258/S
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jimthompson5910 (jim_thompson5910):
no
jimthompson5910 (jim_thompson5910):
Multiply both sides by S.
OpenStudy (anonymous):
1258s ?= I
jimthompson5910 (jim_thompson5910):
yes
\[\Large 3.1 = \log\left(\frac{I}{S}\right)\]
\[\Large 10^{3.1} = \frac{I}{S}\]
\[\Large 1258.92541 = \frac{I}{S}\]
\[\Large 1258.92541S = I\]
\[\Large I = 1258.92541S\]
jimthompson5910 (jim_thompson5910):
The right side says "1258.92541 times S"
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OpenStudy (anonymous):
ok so final answer is the earthquake is 1258 time S for intense than the standard earthquake?
jimthompson5910 (jim_thompson5910):
no, just roughly 1258.92541
jimthompson5910 (jim_thompson5910):
a magnitude 3.1 is roughly 1258.92541 times more intense than a standard earthquake
jimthompson5910 (jim_thompson5910):
S is the intensity of the standard earthquake
OpenStudy (anonymous):
ok thank you a bunch
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jimthompson5910 (jim_thompson5910):
np