Question

solve this trig equation:

Answer 1

\[4\sin ^{2}xcos ^{2}x=1-\cos ^{2x}\]

Answer 2

write cos2x as 1-2sin^2x

Answer 3

or is it cos^2x?

Answer 4

so it becomes:
\[4\sin ^{2}(1-2\sin ^{2}x)=1-(1-2\sin ^{2}x)\]

Answer 5

cos^2

Answer 6

ok forget then what i've written

Answer 7

so..u cant use that

Answer 8

yep, i need to use 1-sin^2x

Answer 9

cos^2 x ==== 1- sin^2 x

Answer 10

Yes

Answer 11

so we get: \[4\sin^2(x) (1-\sin^2(x))=1-1-\sin^2(x)\]