Question

find the exact value of
cot(11pi/6)
cos(11pi/6)
csc(11pi/6)

Answer 1

can I have the full solution please? thankyou!

Answer 2

first remember that 11pi/6 is in 4th quadrant,
so only cos and sec ratio will be positive...
cot(11pi/6)=-cot (2pi-11pi/6)---->as cot x=-cot(-x)=-cot (2pi-x)
=-cot(pi/6)=- sqrt(3)
now cos(11pi/6)=cos (2pi-11pi/6)---->as cos x=cos(-x)=cos (2pi-x)
=cos(pi/6)=sqrt(3)/2
csc(11pi/6)=-csc (2pi-11pi/6)---->as csc x=-csc(-x)=-csc (2pi-x)
=-csc(pi/6)=- 2

Answer 3

@ienarancillo

Answer 4

is this correct? thanks