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find the exact value of cot(11pi/6) cos(11pi/6) csc(11pi/6)
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can I have the full solution please? thankyou!
first remember that 11pi/6 is in 4th quadrant, so only cos and sec ratio will be positive... cot(11pi/6)=-cot (2pi-11pi/6)---->as cot x=-cot(-x)=-cot (2pi-x) =-cot(pi/6)=- sqrt(3) now cos(11pi/6)=cos (2pi-11pi/6)---->as cos x=cos(-x)=cos (2pi-x) =cos(pi/6)=sqrt(3)/2 csc(11pi/6)=-csc (2pi-11pi/6)---->as csc x=-csc(-x)=-csc (2pi-x) =-csc(pi/6)=- 2
@ienarancillo
|dw:1345523017399:dw| is this correct? thanks
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