sec^2 5pi/6 - tan^2 5pi/6 how to solve this? please help! thankyou!

Question

saifoo.khan · Answer

@amistre64

saifoo.khan · Answer

@satellite73

anonymous · Answer

please help.

callisto · Answer

An identity may help you...
$$tan^2x+1 = sec^2x$$
$$=>sec^2x - tan^2x= 1$$
For your question, 
sec^2 5pi/6 - tan^2 5pi/6, 
you can see that x=5pi/6...

Can you get the answer??

anonymous · Answer

sec^2 (5pi/6) - tan^2 (5pi/6) = 1
     
     -> (-2 sqrt of 3/ 3) - (- sqrt of 3 / 3)
             
          = - sqrt of 3 / 3 = 1    ( <- this is my answer... is it correct? thankyou!)

anonymous · Answer

@broderick365 help please? thankyou!

anonymous · Answer

sorry! is it ( - sqrt of 3/ 3) ^2  =   1     ??? :)

anonymous · Answer

and my teacher told us to SIMPLIFY all our answers. how am i going to simplify this? should the answer supposed to be    3 =  1 ??? :D

anonymous · Answer

@hartnn please help? what's the exact answer? thankyou! :)

hartnn · Answer

the exact answer as told by callisto and you also is 1 .

anonymous · Answer

oh. thanks. :)

callisto · Answer

sec^2 (5pi/6) - tan^2 (5pi/6) = 1  
Since the angle is the same, you can use that identity to get the answer - 1.

anonymous · Answer

@Callisto  i thought it was 1? thankyou |dw:1345608020686:dw|