Landon is standing in a hole that is 5.1ft. deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y=-0.005x^2+0.41x-5.1 where x is the horizonal distance of the rock in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizonally from Landon will the rock land?
A. 66.71ft
C. 15.29 ft
D. 7.65 ft

Question

Landon is standing in a hole that is 5.1ft. deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y=-0.005x^2+0.41x-5.1 where x is the horizonal distance of the rock in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizonally from Landon will the rock land?
A. 66.71ft
C. 15.29 ft
D. 7.65 ft

anonymous · Answer

Could you help

cwrw238 · Answer

i'm puzzled by this - i don't think we have enough information to solve it.

anonymous · Answer

idk that is all they had in my test i copied it down cause i got it wrong so i wrote it down correct here

kainui · Answer

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anonymous · Answer

hold on and ill post a pic of the ?

cwrw238 · Answer

it can't be C because that gives a negative  answer

anonymous · Answer

Landon is standing in a hole that is 5.1 ft deep. He throws a rock, and it goes up into the air, out of the hole, and then lands on the ground above. The path of the rock can be modeled by the equation y = -0.005x2 + 0.41x - 5.1, where x is the horizontal distance of the rock, in feet, from Landon and y is the height, in feet, of the rock above the ground. How far horizontally from Landon will the rock land?