What is the 7th term of the geometric sequence –1, 3, –9, …?
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OpenStudy (lgbasallote):
hint: formula for geometric sequence is \[A_n = A_1 r^{n-1}\]
in your problem the first number is -1; you keep multiplying each number by -3; you're looking for the 11th term
does that help?
OpenStudy (anonymous):
so a(n)=-1(r)^n-1
Whats r and n?
OpenStudy (valpey):
Or the 7th term. r is -3 and n is 7 for the 7th term.
OpenStudy (lgbasallote):
hmm weird...it was 11th term a while ago...
OpenStudy (valpey):
Hmm. Either the question was edited or you are going crazy. Are you hearing voices, @lgbasallote ?
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OpenStudy (lgbasallote):
no..but i am seeing things..
OpenStudy (anonymous):
I just typed my question here. Im confused now.
OpenStudy (anonymous):
back to earth guys. thanks
this is what I do right?
OpenStudy (anonymous):
-1(-3)^7-1?
OpenStudy (anonymous):
3^6?
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OpenStudy (lgbasallote):
yes that
OpenStudy (anonymous):
729?
OpenStudy (lgbasallote):
remind me where the -1 went?
OpenStudy (valpey):
I want to believe.
@mother123 yes and no. Careful the -1 is outside the ().
OpenStudy (lgbasallote):
remember you raise -3 to 6 before multiplying to -1
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OpenStudy (anonymous):
-3^6= -729 so then multiply that my -1 so thats 729?
OpenStudy (lgbasallote):
no...
OpenStudy (lgbasallote):
(-3)^6 is 729
OpenStudy (anonymous):
ohh wait you have to you parenthesis?
OpenStudy (lgbasallote):
yes
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