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Mathematics 16 Online
OpenStudy (anonymous):

What is the 7th term of the geometric sequence –1, 3, –9, …?

OpenStudy (lgbasallote):

hint: formula for geometric sequence is \[A_n = A_1 r^{n-1}\] in your problem the first number is -1; you keep multiplying each number by -3; you're looking for the 11th term does that help?

OpenStudy (anonymous):

so a(n)=-1(r)^n-1 Whats r and n?

OpenStudy (valpey):

Or the 7th term. r is -3 and n is 7 for the 7th term.

OpenStudy (lgbasallote):

hmm weird...it was 11th term a while ago...

OpenStudy (valpey):

Hmm. Either the question was edited or you are going crazy. Are you hearing voices, @lgbasallote ?

OpenStudy (lgbasallote):

no..but i am seeing things..

OpenStudy (anonymous):

I just typed my question here. Im confused now.

OpenStudy (anonymous):

back to earth guys. thanks this is what I do right?

OpenStudy (anonymous):

-1(-3)^7-1?

OpenStudy (anonymous):

3^6?

OpenStudy (lgbasallote):

yes that

OpenStudy (anonymous):

729?

OpenStudy (lgbasallote):

remind me where the -1 went?

OpenStudy (valpey):

I want to believe. @mother123 yes and no. Careful the -1 is outside the ().

OpenStudy (lgbasallote):

remember you raise -3 to 6 before multiplying to -1

OpenStudy (anonymous):

-3^6= -729 so then multiply that my -1 so thats 729?

OpenStudy (lgbasallote):

no...

OpenStudy (lgbasallote):

(-3)^6 is 729

OpenStudy (anonymous):

ohh wait you have to you parenthesis?

OpenStudy (lgbasallote):

yes

OpenStudy (anonymous):

oh okayy! got it! thanks so much!

OpenStudy (lgbasallote):

welcome

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